deskjet 1050

The new HP DeskJet 2131 inkjet printer, according to the instructions installed after the installation of the computer, the discovery Scan, copy function is normal use, except printing function can not be used normally.The problem is as follows: Print the test page in the installed printer Assistant can output normally, but the Print button in Word will not print properly, although in the Print list can see the print task, but about 3-5 seconds after

1050 Loop Array Maximum sub-segment and base time limit: 1 second space limit: 131072 KB Score: 10 Difficulty: 2-level algorithm topic collection concerns the cyclic sequence consisting of n integers a[1],a[2],a[3],..., a[n], the sequence as a[i]+a[i+1]+...+a[j] Continuous sub-segments and the maximum value (the loop sequence is the number of n is enclosed in a circle, so you need to consider a sequence such as a[n-1],a[n],a[1],a[2]). When the given i

Label:The following error occurred while MySQL was querying from the library ......... ..... last_errno:1050 last_error:error ' Table ' jiuku_brand_img ' already exists ' on query. Default database: ' WINE_CN '. Query: ' CREATE TABLE ' jiuku_brand_img ' (' fid ' int ') unsigned NOT null DEFAULT ' 0 ', ' img ' varchar (#) NOT NULL, ' Q Ueue ' tinyint (3) unsigned not NULL DEFAULT ' + ', UNIQUE key ' fid ' (' FID ', ' img '), KEY ' fid_2 ' (' FID ')) En

http://www.51nod.com/onlineJudge/questionCode.html#problemId=1050noticeId=13385Reference: http://blog.csdn.net/acdreamers/article/details/38760805#include #includeusing namespaceStd;typedefLong Longll;intn;ll a[1000010];ll Work () {ll temp=0, m=0; for(intI=0; i) {Temp+=A[i]; if(temp0) temp=0; if(mtemp; } returnm;}intMain () {intT; ll sum,sum1,sum2; scanf ("%d",t); while(t--) {sum=0; scanf ("%d",N); for(intI=0; i) {scanf ("%lld",A[i]); Sum+=A[i]; } sum1=Work (); for(intI=0; i) A[i]=-A[i

Delete the MySQL database file, causing the table to not be created. Look at the MySQL log shown below. 150922NBSP;NBSP;9:12:35NBSP;NBSP;INNODB:NBSP;ERROR;NBSP;POSSIBLENBSP;REASONS:INNODB:NBSP;1) Table renamewouldcausetwoforeignkeyconstraintsinnodb:tohave thesameinternalnameincase-insensitivecomparison. INNODB:NBSP;2) table ' CRM '. ' Insight ' existsintheInnoDBinternal datainnodb:dictionarythoughmysqlistryingtorenametable ' CRM '. ' Action_value ' toit. Innodb:haveyoudeletedthe.frmfileandnotuse

Nvidia has officially unveiled Nvidia GTX 1050 and GTX 1050, which are geared toward the mainstream market or the Millennium market. The new two graphics card based on the latest Pascal architecture, 16nm FinFET manufacturing process. Nvidia's two graphics cards have found an excellent balance in performance and power consumption, while also creating a lot of pressure on AMD's Radeon RX 460. T

Kde3.5 + compizfusionwithATIRadeonM9000 @ 1400*1050 -- Linux Release Technology-Debian information. Read the following for details. Debian testing/lenny The holiday is boring and I think of compiz. The last time in ubuntu, both beryl and cf can only be successful under 1024*768. As soon as they increase, the screen of 1/4 on the right will be spent. This is in KDE, and the goal is to make it run at a resolution of 1400*

[CODEVS 1050] Board dyeing 2, codevs1050 Description There is a 5 * N board, some of which have been dyed black, your task is to dye the smallest lattice, so that all the black can be connected together. Http://codevs.cn/problem/1050/ Analysis CODEVS has a very conscientious person in his question. I wrote it only after reading it.Http://codevs.cn/wiki/solution? Problem_id = 1050Solution_ID: 5

1050: Find out immediate family time limit: 1 Sec memory limit: MBSubmitted by: 321 Resolution: 264Submitted State [Discussion Version] Title Description If a, B is the parent of C, then a A, a, B is the parent,c of C is a A, a A, if A is C (outside) grandfather, grandmother, then a B is the grandparent,c of C is a A, B is the grandchild, if A is C (outside) great grandfather, Once grandmother, then A, B is the great-grandparent,c of C is a,

51Nod 1050 Loop Array Maximum sub-segment and portalEmmmmm ... I thought it was an array copy for the maximum sub-segment and ... The amount of ... Not...... Think less of the feeling of reverse thinking ...The maximal sub-segments of the loop array and the conversion into non-circular arrays can be of two kinds, one of the largest sub-segments of the non-cyclic array and (presumably, the kind of continuous, not spanning 1 and n types), and the other

#1050: The longest time limit in a tree:10000msSingle Point time limit:1000msMemory Limit:256MBDescribeLast said, Little Ho got a binary tree toy, the toy is connected by small balls and sticks, and in the process of dismantling it, Little Ho found that he can not only piece together into a two-pronged tree! can also be pieced together into a multi-fork tree-well, is actually more ordinary trees.But anyway, little Ho's favorite toy has been upgraded,

starting from 1) is a line segment, and each time a table is moved, and if you move from room 15th to room 25th, the line 15->25 repeats once. And then to move another table, assuming that this time from room 20th moved to room 30th, the segment 20->30 repeated once, the same segment: 20->25 repeated two times, the problem is converted to the maximum number of repetitions.That would be good, a 205-size array representing the corridor position (200 corridor position), initialized to 0, if 15->25

[I] = (temp [I-1]> 0? Temp [I-1]: 0) + Buf [I]; If (max Max = temp [I]; } Return Max; } The following is an example of two-dimensional scaling: 0-2-7 0 9 2-6 2 -4 1-4 7 -1 8 0-2 We use I j to indicate the start and end rows respectively, and traverse all possibilities: For (I = 1; I For (j = I; j In one of the cases, I = 2 J = 4, which is equivalent to selecting 2 3 4 and 3 rows, so that the combination of those columns can obtain the maximum value, because it is always 2 3 4 rows, therefore

Http://acm.pku.edu.cn/JudgeOnline/problem? Id = 1050 The meaning of the question is very simple. Find its sub-matrix in a matrix to maximize the sum of the sub-Matrix Values. In fact, it is the promotion of the largest sub-segment and problem in two-dimensional space. Let's talk about the one-dimensional situation first: It has arrays A0, A1... An. Find the consecutive sub-segments to maximize the sum of them. Assume that for sub-segments: 9 2-16 2 t

Looks quite intuitive at the very first sight... I thought:Rect [x, y, W + 1, H + 1] = rect [x, y, W, H] + num [x + W + 1, y .. Y + H + 1] + num [x .. X + W + 1, Y + H + 1]-num [x + W + 1, Y + H + 1] But that results in O (N ^ 4) at least. Reference: http://blog.csdn.net/hitwhylz/article/details/11848439. Lesson learned:Usually 2D issue can be converted to 1D problem to solve. Cool thought. And what is more important:Decoding problem thoroughly and identify familiar pattern in disguise from it.

Simple question.#include #include#include#include#include#include#include#includestring>#includeusing namespacestd;Const intmaxn=100000+Ten;CharT[MAXN];CharS[MAXN];intFLAG[MAXN];intMain () {gets (s); Gets (t); memset (Flag,0,sizeofflag); for(intI=0; t[i];i++) flag[t[i]]=1; for(intI=0; s[i];i++) { if(flag[s[i]]==1)Continue; printf ("%c", S[i]); } printf ("\ n"); return 0;}PAT (Advanced level) 1050. String Subtraction (20)

Title Description: For 1-n, the so-called end number is such a number, all its factors add equal to its own, such as 6 has 3 factors 1,2,3,1+2+3=6, then 6 is the end of the number. That is, the end number is equal to the sum of all its factors. Input: There are several groups of test data, and the input N,n data range is small. Output: For each set of inputs, output all of the 1-n in the list. If the

seeks out a method to minimize the time to move all the tables.Your job is-to-write a program to solve the manager ' s problem. Inputthe input consists of T test cases. The number of test cases) (T is given in the first line of the input. Each test case begins with a line containing an integer N, 1#include #include#include#includeusing namespacestd;structnode{intx, y;} data[205];intins[205];BOOLcmpConstNode a,ConstNode b) { if(a.xb.x)return true; Else if(a.x==b.x) {if(A.Yreturn true; Else re

1. Error description1 queries executed, 0 success, 1 errors, 0 warnings query: CREATE TABLE EMP (ID int (8) primary key NOT NULL, ename varchar (20) Not NULL, Eage int (3), Esex varchar (2)) error code: 1050Table ' emp ' already exists execution time: 0 sec Transfer Duration : 0 sec Total time : 0.00 1 sec2. Cause of errorDuplicate execution CREATE DATABASE table SQL statementCREATE TABLE EMP ( ID INT (8) PRIMARY KEY NOT NULL, ename varchar (a) NOT NULL, eage INT (3), esex v

large as 100. The numbers in the array would be in the range [-127,127].OutputOutput the sum of the maximal sub-rectangle.Sample Input40-2-7 0 9 2-6 2-4 1-4 1-18 0-2Sample Output151 /*This problem n^3 not to time out, violence is good*/2#include 3 using namespace std;4#include 5#define N 1016 intSum[n][n]={0},n,x;7 intMain ()8 {9scanf ("%d",n);Ten for(inti=1;ii) One for(intj=1;jj) A { -scanf ("%d",x); -Sum[i][j]=sum[i][j-1]+x;/*Sum[i][j] Represents the number of J before the